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所有问题
当前搜索:
∫cos3xcos2xdx
∫cosx
cos2xcos3xdx
答:
= (1/2)cos2xcos4x + (1/2)cos²2x = (1/2)(1/2)[cos(2x + 4x) + cos(2x - 4x)] + (1/2)(1/2)(1 + cos4x)= (1/4)cos6x + (1/4)cos2x + 1/4 + (1/4)cos4x ∫ cosxcos2x
cos3x
dx = (1/4)∫ dx + (1/4)
∫ cos2x dx
+ (1/4)∫ cos4x ...
积分号
cos
的3次方乘以x乘以
dx
答:
∫cos^3 x dx =∫cosxcos^
2xdx
=∫cosx(1-sin^2)dx =∫cosxdx-∫cosxsin^2xdx =-sinx-1/2∫sin2xsinxdx =-sinx-1/2∫(-1/2(cos(3x)-cosx)dx =-sinx+1/4∫cos3xdx-1/4∫cosxdx =-sinx+1/4*1/3
∫cos3x
d3x+1/4sinx =-3/4sinx-1/12sin3x+c ...
为什么
cos3xcos2x
=1/2(cos5x+cosx)
答:
cos2xcos3x =
cos3xcos2x
=(1/2){cos(3x+2x)+cos(3x-2x)} =1/2(cos5x+cosx)
∫cosx
X cos2x dx
答:
∫cosx·
cos2x dx
= (1/2)∫(
cos3x
+cosx)dx = (1/6)sin3x + (1/2)sinx + C
请问
∫
sin
3xcos2xdx
等于什么?
答:
∫sin
3xcos2xdx
=-1/10cos5x-1/2cosx+C。C为积分常数。解答过程如下:∫sin3xcos2xd(x)=1/2∫(sin5x+sinx)dx =1/2(∫sin5xdx+∫sinxdx)=1/2(∫1/5sin5xd5x+∫sinxdx)= -1/10cos5x-1/2cosx+C
请问
∫
sin
3xcos2xdx
等于多少?
答:
∫sin
3xcos2xdx
=-1/10cos5x-1/2cosx+C。C为积分常数。解答过程如下:∫sin3xcos2xd(x)=1/2∫(sin5x+sinx)dx =1/2(∫sin5xdx+∫sinxdx)=1/2(∫1/5sin5xd5x+∫sinxdx)= -1/10cos5x-1/2cosx+C
积分
∫
sin
3xcos2xdx
怎么解答
答:
∫sin
3xcos2xdx
=-1/10cos5x-1/2cosx+C。C为积分常数。解答过程如下:∫sin3xcos2xd(x)=1/2∫(sin5x+sinx)dx =1/2(∫sin5xdx+∫sinxdx)=1/2(∫1/5sin5xd5x+∫sinxdx)= -1/10cos5x-1/2cosx+C
y’’=
cos2xcos3x
求通解
答:
∵y″=
cos2xcos3x
=(1/2)(cosx+cos5x),∴y′=(1/2)∫cosxdx+(1/2)
∫cos
5xdx=(1/2)sinx+(1/10)sin5x+A,∴y=(1/2)∫sinxdx+(1/10)∫sin5
xdx
+A
∫dx
=-(1/2)cosx-(1/50)cos5x+Ax+B。∴原微分方程的通解是:y=-(1/2)cosx-(1/50)...
求不定积分
∫
e^
3xcos2xdx
∫arccotxdx
答:
= (1/3) (
cos3x
) e^(3x) +(2/3)∫ (sin2x)e^(3x)dx = (1/3) (cos3x) e^(3x) +(2/9)∫ (sin2x)de^(3x)=(1/3) (cos3x) e^(3x) +(2/9)(sin2x)e^(3x) - (4/9)∫ (cos2x)e^(3x) dx (13/9)∫e^
3xcos2xdx
= (1/3) (cos3x) e^(3x) +(2/9)...
cos3x
和cosx的关系
答:
cos3x
=cos(2x+x)=
cos2x
cosx-sin2xsinx=(2cos_x-1)cosx-2(1-cos_x)cosx=4cos_x-3cosx三倍角公式:sin(3α) = 3sinα-4sin3α = 4sinα·sin(60°+α)sin(60°-α)cos(3α) = 4cos3α-3cosα = 4cosα·cos(60°+α)cos(60°-α)tan(3α) = (3tanα-...
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