第2个回答 2022-03-01
1/3 ∫[0,1] y^3 e^(-y^2) dy
= -1/6 ∫[0,1] y^2 de^(-y^2)
= (-1/6) [ y^2 e^(-y^2) + e^(-y^2)]|[0,1]
= (1/6)(1-2/e)
第3个回答 2022-03-02
1/3 ∫[0,1] y^3 e^(-y^2) dy
= -1/6 ∫[0,1] y^2 de^(-y^2)
= (-1/6) [ y^2 e^(-y^2) + e^(-y^2)]|[0,1]
= (1/6)(1-2/e)