解ï¼lim(x->+â)[x-x²ln(1+1/x)]
=lim(x->+â)[(1/x-ln(1+1/x))/(1/x²)] (åååæ¯åé¤x²)
=lim(t->0+)[(t-ln(1+t))/t²] (令t=1/x)
=lim(t->0+)[(1-1/(1+t))/(2t)] (0/0åæéï¼åºç¨ç½æ¯è¾¾æ³å)
=lim(t->0+)[(1/2)/(1+t)]
=(1/2)/(1+0)
=1/2ã
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