高数中求偏导的题目,z^3-3xyz=a^3,求d^2z/dxdy,的二次混合求导

Question

如题所述

Answer 1

用隐函数微分法 
令F[x,y,z] = z³-3xyz-a³ 
z'x = -F'x/F'z = yz/(z²-xy) 
z'y = -F'y/F'z = xz/(z²-xy) 
(z也是y的函数,刚才我当成常数扔了- -!)
z''xy = [z'x]'y = [(yz)'(z² - xy) - yz * (2z z'y - x)]/(z²-xy)² 
= [(z + y z'y)(z²-xy) - 2yz² z'y + xyz]/(z²-xy)² 
= (z³ - yz² z'y - xy² z'y)/(z²-xy)² 
= [z³ - (yz²+xy²)xz/(z²-xy)]/(z²-xy)² 
= z(z^4 - 2xyz³ - x²y²z)/(z²-xy)³

追问

我看过这个，看不懂，，，

额，看错了，，，

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