第2个回答 2012-06-15
解:∫1/(2x+1)^(2/3)-(2x+1)^(1/2))dx
=∫1/(2x+1)^(1/2)((2x+1)^(1/6)-1)dx
令(2x+1)^(1/6)=u,那么:2x+1=u^6,代入得:
∫1/(2x+1)^(2/3)-(2x+1)^(1/2))dx
=(1/2)∫6u^5/u^3(u-1)du=3∫u^2/(u-1)du
=3(u^2/2+u+ln|u-1|+C
=3((2x+1)^(1/3)/2+(2x+1)^(1/6)+ln|(2x+1)^(1/6)-1|)+C