如题所述
Uab = 10 - 2 * 4 = 2V
Rab = R2 = 4Ω
I1 = 2 / (4 + 9) = 2/13 A
用线性叠加:
1 电流源开路,U=10V求出 R1 电流 I1U = 1
2 电压源短路,IS=2A 求出 R1 电流 I1I = 1
3 叠加: I1 = I1U + I1I = 2A