第1个回答 2018-12-05
x-direction = i, y-direction = j, z-direction = k
M1M2 =OM2-OM1 = (-3,4,-6)
M1M3 =OM3-OM1 = (-2,3,-1)
法向量
=M1M2x M1M3
(-3i+4j-6k) x( -2i+3j-k)
=( -9k-j) +(8k-4i) +(12j +18i)
=14i +11j -k
M1(2,-1,4) , 法向量(14,11,-1)
平面的点法方程
14(x-2)+11(y+1)-(z-4) = 0