如题所述
方法如下,请作参考:
ln(1+x)等价无穷小为x
eˣ等价无穷小量为1+x
=lim(x趋于0)3x/(1+x-1)=3
用洛必达法则
=lim(x趋于0)[3/(1+3x)]/eˣ
=3/1=3
lim_(x->0) log(1 + 3 x)/(e^x - 1) = 3