(1)1molN
2(g)与适量H
2(g)起反应生成NH
3(g),放出92.2kJ热量,反应的热化学方程式为:N
2(g)+3H
2(g)=2NH
3(g)△H=-92.2kJ/mol;
故答案为:N
2(g)+3H
2(g)=2NH
3(g)△H=-92.2kJ/mol;
(2)1molN
2(g)与适量O
2(g)起反应生成NO(g),吸收68kJ热量,反应的热化学方程式为:N
2(g)+O
2(g)=NO(g)△H=+68KJ/mol;
故答案为:N
2(g)+O
2(g)=NO(g)△H=+68KJ/mol;
(3)1mol Cu(s)能与
molO
2(g)放出反应放出157kJ热量,则其热化学方程式为:Cu(s)+
O
2(g)=CuO(s)△H=-157kJ/mol,
故答案为:Cu(s)+
O
2(g)=CuO(s)△H=-157kJ/mol;
(4)1molC(石墨)与适量的H
2O(g)反应生成CO(g)和H
2(g),吸收131.5KJ热量,标注物质聚集状态和对应反应焓变写出热化学方程式为:
C(石墨)+H
2O(g)=CO(g)+H
2(g)△H=131.5KJ/mol;
故答案为:C(石墨)+H
2O(g)=CO(g)+H
2(g)△H=131.5KJ/mol;
(5)1molC
8H
18(l)在与O
2(g)中燃烧,生成CO
2(g)和H
2O(l),放出5518kJ热量,该反应的热化学方程式为C
8H
18(l)+
O
2(g)=8CO
2(g)+9H
2O(l)△H=-5518kJ/mol;
故答案为:C
8H
18(l)+
O
2(g)=8CO
2(g)+9H
2O(l)△H=-5518kJ/mol.