C++万年历，输入年月，显示月历

Question

如题所述

Answer 1

#include <stdio.h>
#include <stdlib.h>

int f(int year,int month)
{/*f(年，月)＝年－1，如月<3;否则，f(年，月)＝年*/
if(month<3) return year-1;
else return year;
}

int g(int month)
{/*g(月)＝月＋13，如月<3;否则，g(月)＝月＋1*/
if(month<3) return month+13;
else return month+1;
}

int n(int year,int month,int day)
{
/*N=1461*f(年、月)/4+153*g(月)/5+日*/
return 1461L*f(year,month)/4+153L*g(month)/5+day;
}

int w(int year,int month,int day)
{
/*w=(N-621049)%7(0<=w<7)*/
return(int)((n(year,month,day)%7-621049L%7+7)%7);
}

int date[12][6][7];
int day_tbl[ ][12]={{31,28,31,30,31,30,31,31,30,31,30,31},{31,29,31,30,31,30,31,31,30,31,30,31}};

void printyear()
{
int sw,leap,i,j,k,wd,day;
int year;/*年*/
char title[]={" 日 一 二 三 四 五 六 "};
printf("请输入要查询的年份: ");/*输入年*/
scanf("%d%*c",&year);/*输入年份值和掠过值后的回车*/
sw=w(year,1,1);
leap=year%4==0&&year%100||year%400==0;/*判闰年*/
for(i=0;i<12;i++)
for(j=0;j<6;j++)
for(k=0;k<7;k++)
date[i][j][k]=0;/*日期表置0*/
for(i=0;i<12;i++)/*一年十二个月*/
for(wd=0,day=1;day<=day_tbl[leap][i];day++)
{/*将第i＋1月的日期填入日期表*/
date[i][wd][sw]=day;
sw=++sw%7;/*每星期七天，以0至6计数*/
if(sw==0) wd++;/*日期表每七天一行，星期天开始新的一行*/
}
//printf("\n|===================The Calendar of Year %d ======================|\n|",year);
printf("\n|=================== %d 年日历 ======================|\n|",year);
for(i=0;i<6;i++)
{
/*先测算第i+1月和第i+7月的最大星期数*/
for(wd=0,k=0;k<7;k++)/*日期表的第六行有日期，则wd!=0*/
wd+=date[i][5][k]+date[i+6][5][k];
wd=wd?6:5;
printf("%2d月 %s %2d月 %s|\n|",i+1,title,i+7,title);
for(j=0;j<wd;j++)
{
printf(" ");/*输出四个空白符*/
/*左栏为第i+1月，右栏为第i+7月*/
for(k=0;k<7;k++)
{
if(date[i][j][k])
printf("%4d",date[i][j][k]);
else
printf(" ");
}
printf(" ");/*输出十个空白符*/
for(k=0;k<7;k++)
{
if(date[i+6][j][k])
printf("%4d",date[i+6][j][k]);
else
printf(" ");
}
printf(" |\n|");
}
}
printf("\n\n按回车键继续");
}
void showweekday()
{
int i,j,leap,year,month,day,days=0,sum;
char week[][10] = {"周日","周一","周二","周三","周四","周五","周六"};
printf("请输入年 月 日（中间用空格分隔）: ");
scanf("%d%d%d",&year,&month,&day);
leap=(year%4==0&&year%100||year%400==0);
for(i=0;i<month-1;i++)
days += day_tbl[leap][i];
days += day;
sum = year-1+(year-1)/4-(year-1)/100+(year-1)/400+days;
j = sum % 7; //j是星期几,j=0星期日
printf("%d年%d月%d日是%s\n",year,month,day,week[j]);

}
void menu()
{
printf("\n|==================The Menu =====================|\n");
printf("1 显示一年的日历\n");
printf("2 显示某一天是星期几\n");
printf(" 按其他键退出\n");
printf("\n请选择:\n");
}

void main()
{
char choice;
while (1)
{
menu();
scanf("%c",&choice);
switch (choice)
{
case '1':
system("clear");
printyear();
break;
case '2':
system("clear");
showweekday();
break;
default:
exit(0);
}
while(getchar()!='\n');
}
}

Answer 2

#include <stdio.h>
int isly(int year)
{
return ((!(year%4))&&(year%100)||(!(year%400)));
}
int mtod(int m)
{
const static int mday[]={0,0,31,59,90,120,151,181,212,243,273,304,334};
return mday[m];
}
int dmax(int y,int m)
{
if((m==1||m==3||m==5||m==7||m==8||m==10||m==12))
return 31;
else
{
if(m==2)
{
return 28+(isly(y));
}
else
return 30;
}
}
int day(int y,int m)
{
int lyn=0;
int dn=0;
int weekday;
static int aday[7]={2,3,4,5,6,0,1};
if(y>=1901)
{
for(int i=1901;i<=y;i++)
{
lyn+=isly(i);
}
if(isly(y))
{
if(m<=2)
lyn--;
}
dn=(y-1901)*365+mtod(m)+lyn;
weekday=aday[dn%7];
}
if(y<1901)
{
for(int i=y;i<1901;i++)
{
lyn+=isly(i);
}
if(isly(y))
{
if(m>2)
lyn--;
}
dn=(1901-y)*365-mtod(m)+lyn;
weekday=aday[dn%7];
}
return weekday;
}
void printdate(int y,int m,int wd)
{
int cd=dmax(y,m);
int mdate[40]={0};
printf("\n\n");
printf(" %d-%d\n",y,m);
printf(" --------------------\n");
printf(" 日 一 二 三 四 五 六\n");
for(int i=0;i<cd;i++)
{
mdate[i+wd]=i+1;
}
for(int i=0;i<cd+wd;i++)
{
if(mdate[i]==0)
printf(" ");
else
printf("%3d",mdate[i]);
if((i+1)%7==0)
printf("\n");
}
printf("\n");
}
int main()
{
int y=0,m=0,f=1;
printf("输入年月:");
do
{
f=scanf("%d%d",&y,&m);
if(m<13&&m>0)
{
printdate(y,m,day(y,m));
break;
}
else
{
printf("输入不合法，请重新输入:");
f=1;
fflush(stdin);
}
}
while(1);
return 0;
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