解:
å©ç¨è§å¹³å线çæ§è´¨
QM:MA=OQ:OA=1:4
æ以 åé AM=4åéMQ
设Mï¼x,yï¼
Qï¼x0,y0ï¼
A(4,0)
(x-4,y)=4(x0-x, y0-y)
x-4=4(x0-x), y=4(y0-y)
x0=(5x-4)/4 y0=5y/4
(x0,y0)å¨åx²+y²=1ä¸ï¼
æ以 (5x-4)²/16+(5y)²/16=1
å³ (5x-4)²+(5y)²=16
(x-4/5)²+y²=16/25
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