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æ±Ib = ï¼12V - 0.6Vï¼/100K = 0.114mA.
Ic(theroy) = Ib * beta = 0.114mA * 80 = 9.12mA.
Ic(actual) = 12V /1.5K = 8mA.
9.12mA > 8mA.æ以å¤æè¾¾å°é¥±ååº