如题所述
#include<stdio.h>
void main() { int i,n,k;
for ( i=n=k=0;i<10000;i++ )
if ( (i%3==0)&&(i%5==0)&&(i%7==0) ) {
n++; printf("%5d",i); k++; if ( k%10==0 ) printf("\n");
}
printf("\n");