$\dfrac{16^a}{4^b \cdot 2}$ å¯ä»¥ç®å为 $\dfrac{2^{4a}}{2^{2b+1}}$ã
è¿ä¸æ¥ç®åï¼å¯ä»¥å°ååååæ¯é½é¤ä»¥ $2^{2b+1}$ï¼
$$\frac{2^{4a}}{2^{2b+1}} = 2^{4a-(2b+1)} = 2^{4a-2b-1}$$
å æ¤ï¼$\dfrac{16^a}{4^b \cdot 2} = 2^{4a-2b-1}$ã
çæ¡ä¸º $2^{4a-2b-1}$ã
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