(1)
â«(eˣ+1)dx=eˣ+x+C
è¿ç¨çå
¬å¼ï¼â«eˣdx=eˣ+Cï¼â«Adx=Ax+C (æ¬é¢æ¯ç´æ¥å¥å
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(2)
â«[(x³+x+2)/(x²+1)]dx
=â«[x+ 2/(1+x²)]dx
=½x²+2arctanx +C
è¿ç¨çå
¬å¼ï¼â«xⁿdx=[1/(n+1)]xⁿ⁺¹+Cï¼â«dx/(1+x²)=arctanx +C
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