第1个回答 2015-11-16
y = ln(x+1)
y' = 1/(x+1).................= 0!(-1)^0 /(x+1)^1
y'' = - 1/(x+1)².............= 1!(-1)^1 /(x+1)^2
y''' = 2/(x+1)³..............= 2!(-1)^2 /(x+1)^3
y'''' = -6/(x+1)⁴..........= 3!(-1)^3/(x+1)^4
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y(ⁿ) = ...................= (n-1)!(-1)^(n-1)/(x+1)^n本回答被网友采纳