第3个回答 2020-05-21
(1) lim<x→-3>1/(x-3) = ∞
(2) lim<x→1>lnx = 0
二 (1) lim<x→2>(x^2+5)/(x-3) = -9
(2) lim<x→1>(x^2-3x+2)/(x^2-1) = lim<x→1>(x-2)/(x+1) = -1/2
(3) lim<x→∞>(x^2+x)/(x^4-2x^3+10)
= lim<x→∞>(1/x2+1/x^4)/(1-2/x+10/x^4) = 0
(4) lim<x→∞>x^4/(3x^3+2x^2+1)
= lim<x→∞>x/(3+2/x+1/x^3) = ∞本回答被网友采纳