有两个白炽灯,分别为"220v40w"和"110v60w"则两灯的额定电流是?灯丝电阻是?

Question

如题所述

Answer 1

额定电流 I(220V 40W)=40/220=0.182
I(110V 60W)=60/110=0.545
灯丝电阻 R(220V 40W)= 40/I2=1210欧姆 R(110V 60W)=60/I2=201.67欧姆

Answer 2

L1额定电流=40÷220=0.18A 灯丝热电阻=220²÷40=1210ΩΩ
L2额定电流=60÷110=0.55A 灯丝热电阻=110²÷60=202Ω