我自己做的王爽老师的汇编语言第二版第八章答案,不知道对不对,请会的大侠帮忙看下,

Question

assume cs:code,ds:data,es:table
data segment
db "1975","1976","1977","1978","1979","1980","1981","1982","1983"
db "1984","1985","1986","1987","1988","1989","1990","1991","1992"
db "1993","1994","1995"
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ("year summ ne??")
table ends
stack segment
dw 0,0,0,0,0,0,0,0
stack ends
code segment
start:mov ax,stack
mov ss,ax
mov sp,16
mov ax,data
mov ds,ax
mov ax,table
mov es,ax
mov bx,0
mov si,0
mov di,0
mov cx,21
s: mov ax,ds:[si]
mov es:[di],ax
mov ax,ds:[si+84]
mov es:[di+5],ax
push cx
mov cx,0
mov cx,ds:[bx+84+84]
mov es:[di+10],cx
div cx
mov es:[di+13],cx
add si,4
add di,16
add bx,2
pop cx
loop s
mov ax,4c00h
int 21h
code ends
end start

Answer 1

我编译了你这个，不过执行后会报错。divide overflow。
我把我之前写的作业附上把。。
assume cs:codesg
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
;表示21年的21个字符串
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,464900,5937000
;表示21年公司总收入的21个dword型字符串,32位
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 1152,14430,15257,17800
;16位，表示21年公司雇员人数的21个word型数据
data ends
table segment
db 21 dup('year summ ne ?? ')
table ends
codesg segment
start:
;得到数据的段地址
mov ax,data
mov ds,ax
;处理结果存放位置的段地址
mov ax,table
mov es,ax
;需要生成的数据格式：
;年份(4) 空格 收入(4) 空格 雇员(2) 空格 人均收入(2) 空格
;一共是16个字节也就是10H

;年份是开头到0到50H，每隔4H取一个
;雇员个数与从开头相差54H，每隔4H取一个
;人均收入是与开头相差A8H，每隔2H取一个
;除法需要dx来保存总收入的高位，ax保存总收入的低位
;bp来指定table段的位置,bp从0开始，累加10H
;cx来做21次的循环
mov cx,21
mov di,0
mov si,0
mov bx,0
mov bp,0
myloop:
sub bx,bx
;年份
mov ax,ds:[bx].0[di]
mov es:[bp].0,ax
mov ax,ds:[bx].2[di];
mov es:[bp].2,ax
mov byte ptr es:[bp].4,' '
;总收入
mov ax,ds:[bx].54h[di]
mov es:[bp].5,ax
mov ax,ds:[bx].56h[di]
mov es:[bp].7,ax
mov byte ptr es:[bp].9,' '

;雇员人数
mov ax,ds:[bx].0A8h[si]
mov es:[bp].10,ax
mov byte ptr es:[bp].12,' '
;平均
mov dx,ds:[bx].56h[di]
mov ax,ds:[bx].54h[di]
mov bx,ds:[bx].0A8h[si]
div bx
mov es:[bp].13,ax
mov byte ptr es:[bp].15,' '

;递增
add di,4
add si,2
add bp,10H
loop myloop
;尾巴
mov ax,4c00H
int 21H
codesg ends
end start

Answer 2

dos下就能，不过得上网下masm相关的.exe程序，大概才175kb。很小！
dos下只要打debug就行不过你得先进入。exe程序的文件夹里进行汇编！！