(1)
∫(0->π/2) (sinx)^2.cosx dx
=∫(0->π/2) (sinx)^2 dsinx
=(1/3)[ (sinx)^3]|(0->π/2)
=1/3
(2)
∫(0->π/2) xcosx dx
=∫(0->π/2) x dsinx
=[xsinx]|(0->π/2) - ∫(0->π/2) sinx dx
=π/2 + [cosx]|(0->π/2)
=π/2 - 1
追问没看懂😂,0->是啥,能不能写纸上拍个照,我加财富值
追答∫(0->π/2) xcosx dx
积分
下限=0
上限=π/2
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