使用函数求1到100的偶数和的程序

Question

编写程序

Answer 1

解法1: #include <stdio.h> int F1() { return 50*(1+99)/2; } int F2() { return 50*(2+100)/2; } void main() { printf("Odd number sum=%d,Even number sum=%d\n",F1(),F2()); } 解法2 #include <stdio.h> int F1() { int i,sum=0; for(i=1;i<=100;i+=2) sum+=i; return sum; } int F2() { int i,sum=0; for(i=2;i<=100;i+=2) sum+=i; return sum; } void main() { printf("Odd number sum=%d,Even number sum=%d\n",F1(),F2()); }