sin18度等于多少怎么计算？谢谢

Question

如题所述

Answer 1

解法1.令x = 18°
∴cos3x = sin2x
∴4(cosx)^3 - 3cosx = 2sinxcosx
∵cosx≠ 0
∴4(cosx)^2 - 3 = 2sinx
∴4sinx2 + 2sinx - 1 = 0,
又0 < sinx < 1
∴sinx = (√5 - 1)/4
即sin18° = (√5 - 1)/4.

解法2. 作顶角为36°、腰长为1 的等腰三角形ABC, BD为其底角B的平分线，设AD = x
则AD = BD = BC = x, DC = 1 - x.
由相似三角形得：x2 = 1 - x
∴x = (√ 5 - 1)/2
∴sin18° = x/2 = (√5 - 1)/4.

Answer 2

解：∵sin36°＝cos54°
即sin（2×18°）＝cos（3×18°）
2sin18°cos18°＝4(cos18°)^3－3cos18°
∵cos18°≠0
∴2sin18°＝4(cos18°)^2－3
整理得4(sin18°)＾2＋2sin18°－1＝0

解得sin18°＝（根号5－1）/4

Answer 3

sin18*cos36
=sin18*cos368(2cos18)/(2cos18)
=2sin18*cos18*cos36/(2cos18)
=sin36*cos36/(2cos18)
=(sin72
/2)
/
(2cos18)
=sin72/(4cos18)
=cos18/(4cos18)
=1/4