以下是题主所需c代码,如果对您有帮助望采纳:
#include <stdio.h>
int fun(int n);
int sum(int start, int end);
int main() {
int n = 100;
printf("1~%d中的偶数之和为:%d\n", n, sum(1, n));
return 0;
}
int fun(int n) {
if (n % 2 == 0) {
return n;
} else {
return 0;
}
}
int sum(int start, int end) {
int s = 0;
for (int i = start; i <= end; i++) {
s += fun(i);
}
return s;
}