物理切向加速度 法向加速度

Question

如题所述

Answer 1

切向加速度 at=ε.R=0.5*0.3=0.15m/s^2
ω^2=2εθ=2*0.5(240π/180)=4π/3/s^2

法向加速度an=R.ω^2=0.3*4π/3=0.4π m/s^2

Answer 2

2=121/. 当 t=2s 时 an=(4t+3)/R=(4*2+3)^2/s^2
an=v^2/R=(4t+3)/R ;dt=4m/s=2t^2+3t+4
v=4t+3
at=dv/2 m/