第1个回答 2008-09-01
(a+1/a)(a②+1/a②)(a④+1/a④)(a⑧+1/a⑧)(a拾陆+1/a拾陆)(a②-1)
=a(a-1/a)(a+1/a)(a②+1/a②)(a④+1/a④)(a⑧+1/a⑧)(a拾陆+1/a拾陆)
=a[(a^2-1/a^2)(a②+1/a②)(a④+1/a④)(a⑧+1/a⑧)(a拾陆+1/a拾陆)]
=a[(a^4-1/a^4)(a④+1/a④)(a⑧+1/a⑧)(a拾陆+1/a拾陆)]
=a[(a^8-1/a^8)(a^8+1/a^8)(a16+1/a^16)]
=a[a^32-1/a^32]
=a^33-1/a^31
第2个回答 2008-09-01
统一一下表达:a的n次方写作a^n
乘一个(a-1/a),再除一个(a-1/a),变成了
{(a-1/a)(a+1/a)(a^2+1/a^2)(a^4+1/a^4)(a^8+1/a^8)(a^16+1/a^16)(a^2-1)}/(a-1/a)
={(a^2-1/a^2)(a^2+1/a^2)(a^4+1/a^4)(a^8+1/a^8)(a^16+1/a^16)(a^2-1)}/(a-1/a)
={(a^4-1/a^4)(a^4+1/a^4)(a^8+1/a^8)(a^16+1/a^16)(a^2-1)}/(a-1/a)
={(a^8-1/a^8)(a^8+1/a^8)(a^16+1/a^16)(a^2-1)}/(a-1/a)
=(a^16-1/a^16)(a^16+1/a^16)(a^2-1)/(a-1/a)
=a^33-1/a^31
第3个回答 2008-09-01
=(A2-1)(A2+1) (A4+1) (A8+1) (A16+1) (A32+1)/(A*A2*A4*A8*A16)
=(A64-1)/A31
第4个回答 2008-09-01
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