求各位JAVA大神,帮做下这道题吧,下周要交的。。。

多线程编程
编写生产者/消费者模式程序:生产者向堆栈中压数据,消费者从堆栈中取数据。生产者和消费者共同使用同一个堆栈。
要求:生产者每隔600ms产生一个0~999之间的一个随机数,保存在堆栈中,一共200个。消费者从堆栈中取出200个数据,间隔500ms。试编写堆栈类,编写创建消费者、生产者的线程,并演示两个生产者线程,三个消费者线程运行过程。

第1个回答  推荐于2016-01-15
package StackDemo;

import java.util.Random;
import java.util.Stack;

public class StackDemo {

private static Stack<Integer> stack = new Stack<Integer>();

class Producer implements Runnable {
private String name;
private Random random = new Random();
private int data;

public Producer(String name) {
this.name = name;
}

public synchronized void run() {
while (true) {
if (StackDemo.stack.size() < 200) {

try {
Thread.sleep(600);
} catch (InterruptedException e) {
e.printStackTrace();
}

data = random.nextInt(1000);
StackDemo.stack.push(data);
System.out.println(this.name + "生产了" + data + " 堆栈里还剩下"
+ StackDemo.stack.size() + "个数据");

}
}
}

}

class Customer implements Runnable {
private String name;

public Customer(String name) {
this.name = name;
}

public synchronized void run() {
while (true) {
if (!StackDemo.stack.isEmpty()) {

try {
Thread.sleep(500);
} catch (InterruptedException e) {
e.printStackTrace();
}
int data = StackDemo.stack.pop();
System.out.println(this.name + "消耗了" + data + " 堆栈里还剩下"
+ StackDemo.stack.size() + "个数据");

}
}
}

}

public static void main(String[] args) {
StackDemo stackDemo = new StackDemo();
Producer p1 = stackDemo.new Producer("生产者1");
Producer p2 = stackDemo.new Producer("生产者2");
Customer t1 = stackDemo.new Customer("消费者1");
Customer t2 = stackDemo.new Customer("消费者2");
Customer t3 = stackDemo.new Customer("消费者3");
new Thread(p1).start();
new Thread(p2).start();
new Thread(t1).start();
new Thread(t2).start();
new Thread(t3).start();
}

}追问

好像有个地方出错了,怎么改呀???

追答

线程上有点冲突……等我回头改改

package StackDemo;

import java.util.Random;
import java.util.Stack;

public class StackDemo {

private static Stack stack = new Stack();

class Worker implements Runnable {
private String name;
private Random random = new Random();
private int data;
private boolean isProducer;

public Worker(String name, boolean isProducer) {
this.name = name;
this.isProducer = isProducer;
}

public void run() {
while (true) {
synchronized (this) {
if (isProducer) {
if (StackDemo.stack.size() < 200) {

try {
Thread.sleep(600);
} catch (InterruptedException e) {
e.printStackTrace();
}

data = random.nextInt(1000);
StackDemo.stack.push(data);
System.out.println(Thread.currentThread().getName()
+ this.name + "生产了" + data + " 堆栈里还剩下"
+ StackDemo.stack.size() + "个数据");

}
} else {
if (!StackDemo.stack.isEmpty()) {

try {
Thread.sleep(500);
} catch (InterruptedException e) {
e.printStackTrace();
}
int data = StackDemo.stack.pop();
System.out.println(Thread.currentThread().getName()
+ this.name + "消耗了" + data + " 堆栈里还剩下"
+ StackDemo.stack.size() + "个数据");

}
}
}
}
}

}

public static void main(String[] args) {
StackDemo stackDemo = new StackDemo();
Worker p1 = stackDemo.new Worker("生产者", true);
Worker t1 = stackDemo.new Worker("消费者", false);
new Threa

发不全,你留邮箱吧

追问

谢谢了

还是不正确

我都不知道怎么改

追答

类名根文件名保存一致………

大兄弟你这是啥也不会啊……

追问

保持一致了也不行啊

生产消费停不下来了

追答

不用停下来

追问

不是生产200个么???

追答

容器大小是200。意味着生产者最多能生产200,但是当消费者将其消耗了之后,容器又空了,就又可以生产了

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