limn^2(1-cosπ/n),n趋向无穷大

Question

如题所述

Answer 1

原式=lim(1-cosπ/n)/(1/n^2),n趋向无穷大
=lim(n->∞) [(π/n)方/2]/(1/n^2)
=π方/2本回答被提问者采纳