求C语言编译原理语法分析程序答:for(int j=0;!feof(fp);j++){ c[j]=fgetc(fp);//从流中读取字符 } char keyword[m][t]={"include","int","string","cout","cin","auto","break","case","char","class","const","continue","default","delete","do","double","else","enum","extern","float","for",...
编译原理 不能被5整除的偶整数的正规文法和正规式答:分析可知不能被5整除的偶整数的情况是所有两位以上不以0结尾的偶数(2,4,6,8),不包括0。因此,正则表达式为:([1-9][0-9]*[2,4,6,8])|[2,4,6,8]。正规文法为:S-> A | [2,4,6,8]A->B [2,4,6,8]B->[1-9] C C->[0-9] C | ε ...
求 编译原理 语法分析程序答:char G[10][10]={"E->TR","R->+TR","R->e","T->FW","W->*FW","W->e","F->(E)","F->i"};//存储文法中的产生式 char VN[6]={'E','R','T','W','F'};//存储非终结符 char VT[6]={'i','+','*','(',')','#'};//存储终结符 char SELECT[10][...