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编个C语言程序,用二分法求方程x^3-x^4+4x^2-1=
0
在区间[0,1]内的根...
答:
include<stdio.h> include<math.h> int main(){
double
x1=0,x2=1,x3;double function(double);while(fabs(x1-x2)<=0.01){x3=(x1+x2)/2;if(function(x1)*function(x2)<=0)x2=x3;else x1=x3;} printf("The root of this equation is %f\n",x3);return 0;} double function...
c++ 用梯形公式计算sinπx在0到1上的积分
答:
一楼程序没有错,但是不是题目里写的梯形公式,而是矩形公式。所以,正确的写法应该是:include<iostream> include<cmath> define PAI 3.141592653589793 define DT 0.00000001
double
f(double x){ return sin(x*PAI);} using namespace std;void main(){ double x=0,s=0;double last_fx = f...
用二分法求方程2x^3-4x^2+3x-6=0的根,要求误差小于10^(-5),用c语言...
答:
{ return 2*pow(d,3)-4*d*d+3*d-6;} void main(){ int k=0;
double
a,b,limit;printf("\nplease input the 区间:");scanf(""%lf %lf",&a,&b);printf("\nplease input the 解的精确程度:");scanf("%lf",&limit);if(f(a)*f(b)>0)printf("\n 无法用二分法求解");...
用牛顿迭代法求下列方程在1.5附近的根:2(x)∧3-4(x)∧2+3x-6=0...
答:
include<iostream> include<cmath> using namespace std;int main(){ double diedai(double a,double b,double c,
double d
,double x);double a,b,c,d;double x=3.0; //因为迭代法算的只是近似值,所以和标准答案还是有出入的;cout<<"请依次输入方程四个系数:";cin>>a>>b>>c>>d;x=...
编程采用牛顿法求方程编程采用牛顿法求方程2X^4-3X^3+4X^2-6X+3=0...
答:
Author :wacs5 Date :20081209(YYYYMMDD)Function :牛顿迭代法求方程的根 ===*/ include <stdio.h> include <conio.h> include <math.h> define MAX_DIEDAI_TIME 200 main(){ int n=0;
double
x=1.2; /*初值*/ double jingdu=1e-6; /*精度*/ double function(double x);double ...
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