C语言程序:输入1-12输出该月日历 2018年的答:include<stdlib.h>#include<stdio.h>int main(){int n, i;int month[12]={31,28,31,30,31,30,31,31,30,31,30,31};int day = 0, days;printf("Please input n:");scanf("%d", &n);if(n==0)exit(0);for(i = 0; i < n-1; i++){day+=month[i];}days = day % ...
C语言循环结构求教从键盘上输入年、月、日,计算自当年元旦到这个日期...答:day,i,sum;scanf("%d",&year);scanf("%d",&month);scanf("%d",&day);if(isLeapYear(year))days[1]=29;sum=0;for(i=0,i<month-1;i++)sum+=days[i];sum+=(day-1);printf("从%d年1月1日到%d年%d月%d日总共有%d天\n",year,year,month,day,sum);} 求采纳,不懂可追问。
用C语言定义一个包含数组的Date类型的函数,输出年,月,日答://定义结构体变量inti,count,mon[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};printf("请输入日期(年月日):");scanf("%d",&dt.y);scanf("%d",&dt.m);scanf("%d",&dt.d);count=dt.d;//把dt.d计入总天数for(i=0;i2&&(dt.y%4==0&&dt.y%100!=0||dt....
C语言输入年份月份,输出天数。答:include <stdio.h>main(){int year,day,d,month,leap;int i;int Month[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};printf("输入年份:\n");scanf("%d",&year);printf("输入月份:\n");scanf("%d",&month);if( (year%4!=0) ||( (year%100==0)&& (year%400!=0))...